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2100013000231 = 4063751677363
BaseRepresentation
bin11110100011110010100…
…001110110011000100111
321102202111111221200011211
4132203302201312120213
5233401311312001411
64244422130412251
7304502164660066
oct36436241663047
97382444850154
102100013000231
1173a679656183
1229abb6131087
13123051976153
14738d95361dd
153995d434221
hex1e8f2876627

2100013000231 has 4 divisors (see below), whose sum is σ = 2100064718232. Its totient is φ = 2099961282232.

The previous prime is 2100013000139. The next prime is 2100013000237. The reversal of 2100013000231 is 1320003100012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2100013000231 - 27 = 2100013000103 is a prime.

It is a super-2 number, since 2×21000130002312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2100013000237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25798045 + ... + 25879318.

It is an arithmetic number, because the mean of its divisors is an integer number (525016179558).

Almost surely, 22100013000231 is an apocalyptic number.

2100013000231 is a deficient number, since it is larger than the sum of its proper divisors (51718001).

2100013000231 is an equidigital number, since it uses as much as digits as its factorization.

2100013000231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51718000.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 2100013000231 its reverse (1320003100012), we get a palindrome (3420016100243).

The spelling of 2100013000231 in words is "two trillion, one hundred billion, thirteen million, two hundred thirty-one", and thus it is an aban number.

Divisors: 1 40637 51677363 2100013000231