Base | Representation |
---|---|
bin | 1001100011001101100111… |
… | …11001100110110101111001 |
3 | 2202100200112200211010001112 |
4 | 10301212303321212311321 |
5 | 10223040240003124423 |
6 | 112355440035130105 |
7 | 4265165110655024 |
oct | 461466371466571 |
9 | 82320480733045 |
10 | 21001113333113 |
11 | 6767581a84641 |
12 | 24321a6443935 |
13 | b9452011ac64 |
14 | 5286604b41bb |
15 | 266449218a78 |
hex | 1319b3e66d79 |
21001113333113 has 32 divisors (see below), whose sum is σ = 21654312556800. Its totient is φ = 20356128817920.
The previous prime is 21001113333103. The next prime is 21001113333131. The reversal of 21001113333113 is 31133331110012.
It is a cyclic number.
It is not a de Polignac number, because 21001113333113 - 222 = 21001109138809 is a prime.
It is a super-2 number, since 2×210011133331132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21001113333103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5450585495 + ... + 5450589347.
It is an arithmetic number, because the mean of its divisors is an integer number (676697267400).
Almost surely, 221001113333113 is an apocalyptic number.
It is an amenable number.
21001113333113 is a deficient number, since it is larger than the sum of its proper divisors (653199223687).
21001113333113 is a wasteful number, since it uses less digits than its factorization.
21001113333113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5889.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 21001113333113 its reverse (31133331110012), we get a palindrome (52134444443125).
The spelling of 21001113333113 in words is "twenty-one trillion, one billion, one hundred thirteen million, three hundred thirty-three thousand, one hundred thirteen".
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