Search a number
-
+
210011311133000 = 235313237910698317
BaseRepresentation
bin101111110000000100010001…
…100110010101000101001000
31000112120212220100202101212122
4233300010101212111011020
5210011311131122224000
62022353510415230412
762143550032013216
oct5760042146250510
91015525810671778
10210011311133000
1160a0932a172a73
121b679723218408
139024c9b939cc0
1439c085d093cb6
151942d2202e085
hexbf0111995148

210011311133000 has 512 divisors, whose sum is σ = 559819233792000. Its totient is φ = 73155040358400.

The previous prime is 210011311132993. The next prime is 210011311133017. The reversal of 210011311133000 is 331113110012.

It is a super-3 number, since 3×2100113111330003 (a number of 44 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 210011311133000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 25250844842 + ... + 25250853158.

It is an arithmetic number, because the mean of its divisors is an integer number (1093396941000).

Almost surely, 2210011311133000 is an apocalyptic number.

210011311133000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 210011311133000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (279909616896000).

210011311133000 is an abundant number, since it is smaller than the sum of its proper divisors (349807922659000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

210011311133000 is a wasteful number, since it uses less digits than its factorization.

210011311133000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9522 (or 9508 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 210011311133000 its reverse (331113110012), we get a palindrome (210342424243012).

The spelling of 210011311133000 in words is "two hundred ten trillion, eleven billion, three hundred eleven million, one hundred thirty-three thousand".