Base | Representation |
---|---|
bin | 111110100101101… |
… | …0011000000011001 |
3 | 12102100201211001000 |
4 | 1331023103000121 |
5 | 13300112112213 |
6 | 544220415213 |
7 | 103020445455 |
oct | 17513230031 |
9 | 5370654030 |
10 | 2100113433 |
11 | 988506340 |
12 | 4a73a7509 |
13 | 27612a692 |
14 | 15ccb9665 |
15 | c458ac73 |
hex | 7d2d3019 |
2100113433 has 32 divisors (see below), whose sum is σ = 3404016000. Its totient is φ = 1269086400.
The previous prime is 2100113423. The next prime is 2100113467. The reversal of 2100113433 is 3343110012.
It is not a de Polignac number, because 2100113433 - 210 = 2100112409 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2100113413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 93523 + ... + 113783.
It is an arithmetic number, because the mean of its divisors is an integer number (106375500).
Almost surely, 22100113433 is an apocalyptic number.
It is an amenable number.
2100113433 is a deficient number, since it is larger than the sum of its proper divisors (1303902567).
2100113433 is a wasteful number, since it uses less digits than its factorization.
2100113433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20630 (or 20624 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
The square root of 2100113433 is about 45826.9945883428. The cubic root of 2100113433 is about 1280.6022217051.
Adding to 2100113433 its reverse (3343110012), we get a palindrome (5443223445).
It can be divided in two parts, 210011 and 3433, that added together give a square (213444 = 4622).
The spelling of 2100113433 in words is "two billion, one hundred million, one hundred thirteen thousand, four hundred thirty-three".
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