Base | Representation |
---|---|
bin | 11110100011111010001… |
… | …011010100010010010011 |
3 | 21102202211110101112122002 |
4 | 132203322023110102103 |
5 | 233402042133423443 |
6 | 4244442552504215 |
7 | 304505313414242 |
oct | 36437213242223 |
9 | 7382743345562 |
10 | 2100141311123 |
11 | 73a735024039 |
12 | 29b0310ab06b |
13 | 12307241cb5b |
14 | 7390c5b6959 |
15 | 3996982c2b8 |
hex | 1e8fa2d4493 |
2100141311123 has 32 divisors (see below), whose sum is σ = 2250620121600. Its totient is φ = 1954043917056.
The previous prime is 2100141311119. The next prime is 2100141311153. The reversal of 2100141311123 is 3211131410012.
It is a cyclic number.
It is not a de Polignac number, because 2100141311123 - 22 = 2100141311119 is a prime.
It is a super-2 number, since 2×21001413111232 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2100141311095 and 2100141311104.
It is not an unprimeable number, because it can be changed into a prime (2100141311113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 126255215 + ... + 126271847.
It is an arithmetic number, because the mean of its divisors is an integer number (70331878800).
Almost surely, 22100141311123 is an apocalyptic number.
2100141311123 is a deficient number, since it is larger than the sum of its proper divisors (150478810477).
2100141311123 is a wasteful number, since it uses less digits than its factorization.
2100141311123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17291.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 2100141311123 its reverse (3211131410012), we get a palindrome (5311272721135).
The spelling of 2100141311123 in words is "two trillion, one hundred billion, one hundred forty-one million, three hundred eleven thousand, one hundred twenty-three".
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