2100300000033 has 4 divisors (see below), whose sum is σ = 2800400000048. Its totient is φ = 1400200000020.

The previous prime is 2100299999989. The next prime is 2100300000047. The reversal of 2100300000033 is 3300000030012.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2100300000033 - 2¹³ = 2100299991841 is a prime.

It is a super-2 number, since 2×2100300000033² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2100299999964 and 2100300000018.

It is not an unprimeable number, because it can be changed into a prime (2100300000233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350050000003 + ... + 350050000008.

It is an arithmetic number, because the mean of its divisors is an integer number (700100000012).

Almost surely, 2^{2100300000033} is an apocalyptic number.

It is an amenable number.

2100300000033 is a deficient number, since it is larger than the sum of its proper divisors (700100000015).

2100300000033 is an equidigital number, since it uses as much as digits as its factorization.

2100300000033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 700100000014.

The product of its (nonzero) digits is 54, while the sum is 12.

Adding to 2100300000033 its reverse (3300000030012), we get a palindrome (5400300030045).

The spelling of 2100300000033 in words is "two trillion, one hundred billion, three hundred million, thirty-three", and thus it is an aban number.