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21003011303 = 121317314931
BaseRepresentation
bin10011100011111000…
…001000010011100111
32000012201212112002112
4103203320020103213
5321003232330203
613352035231235
71342321436051
oct234370102347
960181775075
1021003011303
1189a871a28a
1240a1a4851b
131c9942a651
1410335b88d1
1582dd446d8
hex4e3e084e7

21003011303 has 4 divisors (see below), whose sum is σ = 21020327448. Its totient is φ = 20985695160.

The previous prime is 21003011291. The next prime is 21003011317. The reversal of 21003011303 is 30311030012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21003011303 - 24 = 21003011287 is a prime.

It is a super-2 number, since 2×210030113032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21003011353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8656253 + ... + 8658678.

It is an arithmetic number, because the mean of its divisors is an integer number (5255081862).

Almost surely, 221003011303 is an apocalyptic number.

21003011303 is a deficient number, since it is larger than the sum of its proper divisors (17316145).

21003011303 is a wasteful number, since it uses less digits than its factorization.

21003011303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17316144.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 21003011303 its reverse (30311030012), we get a palindrome (51314041315).

The spelling of 21003011303 in words is "twenty-one billion, three million, eleven thousand, three hundred three".

Divisors: 1 1213 17314931 21003011303