Base | Representation |
---|---|
bin | 101111110000010110110100… |
… | …011000110000010101011101 |
3 | 1000112122210021222210211222110 |
4 | 233300112310120300111131 |
5 | 210012122420331130023 |
6 | 2022411002245104233 |
7 | 62145153323466204 |
oct | 5760266430602535 |
9 | 1015583258724873 |
10 | 210031222130013 |
11 | 60a168174317a9 |
12 | 1b68155b3b8079 |
13 | 9026b22a5173b |
14 | 39c17cb60c23b |
15 | 19435da068a93 |
hex | bf05b463055d |
210031222130013 has 4 divisors (see below), whose sum is σ = 280041629506688. Its totient is φ = 140020814753340.
The previous prime is 210031222129991. The next prime is 210031222130017. The reversal of 210031222130013 is 310031222130012.
210031222130013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 210031222130013 - 225 = 210031188575581 is a prime.
It is a super-2 number, since 2×2100312221300132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (210031222130017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35005203688333 + ... + 35005203688338.
It is an arithmetic number, because the mean of its divisors is an integer number (70010407376672).
Almost surely, 2210031222130013 is an apocalyptic number.
It is an amenable number.
210031222130013 is a deficient number, since it is larger than the sum of its proper divisors (70010407376675).
210031222130013 is an equidigital number, since it uses as much as digits as its factorization.
210031222130013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70010407376674.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 210031222130013 its reverse (310031222130012), we get a palindrome (520062444260025).
Subtracting 210031222130013 from its reverse (310031222130012), we obtain a palindrome (99999999999999).
The spelling of 210031222130013 in words is "two hundred ten trillion, thirty-one billion, two hundred twenty-two million, one hundred thirty thousand, thirteen".
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