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21003201403 = 89450752361
BaseRepresentation
bin10011100011111000…
…110110101101111011
32000012202020011212021
4103203320312231323
5321003304421103
613352043255311
71342323160222
oct234370665573
960182204767
1021003201403
1189a883a098
1240a1b1a537
131c99496032
141033627cb9
1582dd80bbd
hex4e3e36b7b

21003201403 has 8 divisors (see below), whose sum is σ = 21244310640. Its totient is φ = 20762206080.

The previous prime is 21003201347. The next prime is 21003201451. The reversal of 21003201403 is 30410230012.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21003201403 - 29 = 21003200891 is a prime.

It is a super-2 number, since 2×210032014032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21003201503) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 374943 + ... + 427303.

It is an arithmetic number, because the mean of its divisors is an integer number (2655538830).

Almost surely, 221003201403 is an apocalyptic number.

21003201403 is a deficient number, since it is larger than the sum of its proper divisors (241109237).

21003201403 is an equidigital number, since it uses as much as digits as its factorization.

21003201403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56957.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 21003201403 its reverse (30410230012), we get a palindrome (51413431415).

The spelling of 21003201403 in words is "twenty-one billion, three million, two hundred one thousand, four hundred three".

Divisors: 1 89 4507 52361 401123 4660129 235991027 21003201403