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210033340133 = 602934837177
BaseRepresentation
bin1100001110011011110…
…1100110111011100101
3202002010120210011200112
43003212331212323211
511420122013341013
6240253223222405
721113551635341
oct3034675467345
9662116704615
10210033340133
1181090388141
12348578a7a05
1316a62bb0a26
14a246842621
1556e421aba8
hex30e6f66ee5

210033340133 has 4 divisors (see below), whose sum is σ = 210068183340. Its totient is φ = 209998496928.

The previous prime is 210033340123. The next prime is 210033340177. The reversal of 210033340133 is 331043330012.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 205333140769 + 4700199364 = 453137^2 + 68558^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-210033340133 is a prime.

It is a super-2 number, since 2×2100333401332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 210033340099 and 210033340108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (210033340123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17412560 + ... + 17424617.

It is an arithmetic number, because the mean of its divisors is an integer number (52517045835).

Almost surely, 2210033340133 is an apocalyptic number.

It is an amenable number.

210033340133 is a deficient number, since it is larger than the sum of its proper divisors (34843207).

210033340133 is an equidigital number, since it uses as much as digits as its factorization.

210033340133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34843206.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 210033340133 its reverse (331043330012), we get a palindrome (541076670145).

The spelling of 210033340133 in words is "two hundred ten billion, thirty-three million, three hundred forty thousand, one hundred thirty-three".

Divisors: 1 6029 34837177 210033340133