Base | Representation |
---|---|
bin | 101111110000100000111110… |
… | …101100101011101001111001 |
3 | 1000112200211110100200022110212 |
4 | 233300200332230223221321 |
5 | 210012312241412402441 |
6 | 2022420005033120505 |
7 | 62146020564462533 |
oct | 5760407654535171 |
9 | 1015624410608425 |
10 | 210042132544121 |
11 | 60a20406041369 |
12 | 1b6836a5259135 |
13 | 9027b71240787 |
14 | 39c214463c853 |
15 | 1943a27d0deeb |
hex | bf083eb2ba79 |
210042132544121 has 8 divisors (see below), whose sum is σ = 211055009236800. Its totient is φ = 209029420157040.
The previous prime is 210042132544109. The next prime is 210042132544141. The reversal of 210042132544121 is 121445231240012.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 210042132544121 - 210 = 210042132543097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (210042132544141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38513126 + ... + 43627343.
It is an arithmetic number, because the mean of its divisors is an integer number (26381876154600).
Almost surely, 2210042132544121 is an apocalyptic number.
It is an amenable number.
210042132544121 is a deficient number, since it is larger than the sum of its proper divisors (1012876692679).
210042132544121 is a wasteful number, since it uses less digits than its factorization.
210042132544121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82152799.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 210042132544121 its reverse (121445231240012), we get a palindrome (331487363784133).
The spelling of 210042132544121 in words is "two hundred ten trillion, forty-two billion, one hundred thirty-two million, five hundred forty-four thousand, one hundred twenty-one".
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