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2100425111 = 2957710323
BaseRepresentation
bin111110100110001…
…1111000110010111
312102101022122120122
41331030133012113
513300202100421
6544231222155
7103023214241
oct17514370627
95371278518
102100425111
119886a9524
124a751795b
132762094c5
1415cd5b091
15c45ed2ab
hex7d31f197

2100425111 has 4 divisors (see below), whose sum is σ = 2101138392. Its totient is φ = 2099711832.

The previous prime is 2100425083. The next prime is 2100425147. The reversal of 2100425111 is 1115240012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2100425111 - 210 = 2100424087 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2100425111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2100425611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352205 + ... + 358118.

It is an arithmetic number, because the mean of its divisors is an integer number (525284598).

Almost surely, 22100425111 is an apocalyptic number.

2100425111 is a deficient number, since it is larger than the sum of its proper divisors (713281).

2100425111 is an equidigital number, since it uses as much as digits as its factorization.

2100425111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 713280.

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 2100425111 is about 45830.3950561197. The cubic root of 2100425111 is about 1280.6655699969.

Adding to 2100425111 its reverse (1115240012), we get a palindrome (3215665123).

The spelling of 2100425111 in words is "two billion, one hundred million, four hundred twenty-five thousand, one hundred eleven".

Divisors: 1 2957 710323 2100425111