Base | Representation |
---|---|
bin | 11110100100110011011… |
… | …000101010101010101111 |
3 | 21102212022100102110220002 |
4 | 132210303120222222233 |
5 | 233411023341040413 |
6 | 4245122120414515 |
7 | 304541146530416 |
oct | 36446330525257 |
9 | 7385270373802 |
10 | 2101101111983 |
11 | 740087890695 |
12 | 29b25a61743b |
13 | 123196223963 |
14 | 7399dc5c47d |
15 | 399c3c1c958 |
hex | 1e93362aaaf |
2101101111983 has 4 divisors (see below), whose sum is σ = 2106953761680. Its totient is φ = 2095248462288.
The previous prime is 2101101111937. The next prime is 2101101112027. The reversal of 2101101111983 is 3891111011012.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2101101111983 - 212 = 2101101107887 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2101101111283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2926324310 + ... + 2926325027.
It is an arithmetic number, because the mean of its divisors is an integer number (526738440420).
Almost surely, 22101101111983 is an apocalyptic number.
2101101111983 is a deficient number, since it is larger than the sum of its proper divisors (5852649697).
2101101111983 is an equidigital number, since it uses as much as digits as its factorization.
2101101111983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5852649696.
The product of its (nonzero) digits is 432, while the sum is 29.
Adding to 2101101111983 its reverse (3891111011012), we get a palindrome (5992212122995).
The spelling of 2101101111983 in words is "two trillion, one hundred one billion, one hundred one million, one hundred eleven thousand, nine hundred eighty-three".
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