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210113100215 = 5149282031007
BaseRepresentation
bin1100001110101110110…
…1110111100110110111
3202002100010212101221122
43003223231313212313
511420302423201330
6240305152534155
721115540612124
oct3035355674667
9662303771848
10210113100215
1181121405067
123487a55135b
1316a76588b45
14a25328574b
1556eb2235e5
hex30ebb779b7

210113100215 has 8 divisors (see below), whose sum is σ = 253827907200. Its totient is φ = 166962355552.

The previous prime is 210113100187. The next prime is 210113100229. The reversal of 210113100215 is 512001311012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 210113100215 - 218 = 210112838071 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 210113100193 and 210113100202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 141014759 + ... + 141016248.

It is an arithmetic number, because the mean of its divisors is an integer number (31728488400).

Almost surely, 2210113100215 is an apocalyptic number.

210113100215 is a deficient number, since it is larger than the sum of its proper divisors (43714806985).

210113100215 is a wasteful number, since it uses less digits than its factorization.

210113100215 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 282031161.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 210113100215 its reverse (512001311012), we get a palindrome (722114411227).

The spelling of 210113100215 in words is "two hundred ten billion, one hundred thirteen million, one hundred thousand, two hundred fifteen".

Divisors: 1 5 149 745 282031007 1410155035 42022620043 210113100215