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21100022113 = 54713856703
BaseRepresentation
bin10011101001101010…
…001100100101100001
32000110111102011220111
4103221222030211201
5321203101201423
613405422411321
71344610141312
oct235152144541
960414364814
1021100022113
118a48459a05
12410a430b41
131cb35656b1
14104242c609
1583760860d
hex4e9a8c961

21100022113 has 4 divisors (see below), whose sum is σ = 21103884288. Its totient is φ = 21096159940.

The previous prime is 21100022081. The next prime is 21100022117. The reversal of 21100022113 is 31122000112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21100022113 - 25 = 21100022081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21100022093 and 21100022102.

It is not an unprimeable number, because it can be changed into a prime (21100022117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1922881 + ... + 1933822.

It is an arithmetic number, because the mean of its divisors is an integer number (5275971072).

Almost surely, 221100022113 is an apocalyptic number.

It is an amenable number.

21100022113 is a deficient number, since it is larger than the sum of its proper divisors (3862175).

21100022113 is an equidigital number, since it uses as much as digits as its factorization.

21100022113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3862174.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21100022113 its reverse (31122000112), we get a palindrome (52222022225).

The spelling of 21100022113 in words is "twenty-one billion, one hundred million, twenty-two thousand, one hundred thirteen".

Divisors: 1 5471 3856703 21100022113