Base | Representation |
---|---|
bin | 1100010010000010100… |
… | …1110000000001011111 |
3 | 202011122001000012200121 |
4 | 3010200221300001133 |
5 | 11424112302304043 |
6 | 240533240135411 |
7 | 21146543501236 |
oct | 3044051600137 |
9 | 664561005617 |
10 | 211001213023 |
11 | 81537758397 |
12 | 34a87a67567 |
13 | 16b8857c993 |
14 | a2d91c9b1d |
15 | 574e1a2ded |
hex | 3120a7005f |
211001213023 has 4 divisors (see below), whose sum is σ = 211004241280. Its totient is φ = 210998184768.
The previous prime is 211001213011. The next prime is 211001213029. The reversal of 211001213023 is 320312100112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211001213023 - 25 = 211001212991 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 211001212988 and 211001213006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211001213029) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1407090 + ... + 1549807.
It is an arithmetic number, because the mean of its divisors is an integer number (52751060320).
Almost surely, 2211001213023 is an apocalyptic number.
211001213023 is a deficient number, since it is larger than the sum of its proper divisors (3028257).
211001213023 is an equidigital number, since it uses as much as digits as its factorization.
211001213023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3028256.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 211001213023 its reverse (320312100112), we get a palindrome (531313313135).
The spelling of 211001213023 in words is "two hundred eleven billion, one million, two hundred thirteen thousand, twenty-three".
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