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2110023213103 = 13162309477931
BaseRepresentation
bin11110101101000111001…
…011110010000000101111
321110201100010221011201201
4132231013023302000233
5234032311420304403
64253155320150331
7305305225246141
oct36550713620057
97421303834651
102110023213103
11743946106283
122a0b2a6083a7
13123c887cb030
14741a8b96c91
1539d4715d21d
hex1eb472f202f

2110023213103 has 4 divisors (see below), whose sum is σ = 2272332691048. Its totient is φ = 1947713735160.

The previous prime is 2110023213079. The next prime is 2110023213119. The reversal of 2110023213103 is 3013123200112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2110023213103 - 217 = 2110023082031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2110023217103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81154738953 + ... + 81154738978.

It is an arithmetic number, because the mean of its divisors is an integer number (568083172762).

Almost surely, 22110023213103 is an apocalyptic number.

2110023213103 is a deficient number, since it is larger than the sum of its proper divisors (162309477945).

2110023213103 is a wasteful number, since it uses less digits than its factorization.

2110023213103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162309477944.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2110023213103 its reverse (3013123200112), we get a palindrome (5123146413215).

The spelling of 2110023213103 in words is "two trillion, one hundred ten billion, twenty-three million, two hundred thirteen thousand, one hundred three".

Divisors: 1 13 162309477931 2110023213103