21100313110413 has 4 divisors (see below), whose sum is σ = 28133750813888. Its totient is φ = 14066875406940.

The previous prime is 21100313110367. The next prime is 21100313110463. The reversal of 21100313110413 is 31401131300112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21100313110413 - 2¹² = 21100313106317 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21100313110413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21100313110463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3516718851733 + ... + 3516718851738.

It is an arithmetic number, because the mean of its divisors is an integer number (7033437703472).

Almost surely, 2^{21100313110413} is an apocalyptic number.

It is an amenable number.

21100313110413 is a deficient number, since it is larger than the sum of its proper divisors (7033437703475).

21100313110413 is an equidigital number, since it uses as much as digits as its factorization.

21100313110413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7033437703474.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 21100313110413 its reverse (31401131300112), we get a palindrome (52501444410525).

The spelling of 21100313110413 in words is "twenty-one trillion, one hundred billion, three hundred thirteen million, one hundred ten thousand, four hundred thirteen".