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211004041331 = 533981208327
BaseRepresentation
bin1100010010000011010…
…0100010100001110011
3202011122020022220101202
43010200310202201303
511424114013310311
6240533420521415
721146606521106
oct3044064424163
9664566286352
10211004041331
118153930a336
1234a889b026b
1316b89030135
14a2d972473d
15574e560e3b
hex3120d22873

211004041331 has 4 divisors (see below), whose sum is σ = 214985249712. Its totient is φ = 207022832952.

The previous prime is 211004041309. The next prime is 211004041351. The reversal of 211004041331 is 133140400112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211004041331 - 214 = 211004024947 is a prime.

It is a super-2 number, since 2×2110040413312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211004041351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1990604111 + ... + 1990604216.

It is an arithmetic number, because the mean of its divisors is an integer number (53746312428).

Almost surely, 2211004041331 is an apocalyptic number.

211004041331 is a deficient number, since it is larger than the sum of its proper divisors (3981208381).

211004041331 is an equidigital number, since it uses as much as digits as its factorization.

211004041331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3981208380.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 211004041331 its reverse (133140400112), we get a palindrome (344144441443).

The spelling of 211004041331 in words is "two hundred eleven billion, four million, forty-one thousand, three hundred thirty-one".

Divisors: 1 53 3981208327 211004041331