21101001314333 has 4 divisors (see below), whose sum is σ = 21828622049340. Its totient is φ = 20373380579328.

The previous prime is 21101001314329. The next prime is 21101001314359. The reversal of 21101001314333 is 33341310010112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6920256287044 + 14180745027289 = 2630638^2 + 3765733^2 .

It is a cyclic number.

It is not a de Polignac number, because 21101001314333 - 2² = 21101001314329 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21101001314299 and 21101001314308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21101001314383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363810367460 + ... + 363810367517.

It is an arithmetic number, because the mean of its divisors is an integer number (5457155512335).

Almost surely, 2^{21101001314333} is an apocalyptic number.

It is an amenable number.

21101001314333 is a deficient number, since it is larger than the sum of its proper divisors (727620735007).

21101001314333 is an equidigital number, since it uses as much as digits as its factorization.

21101001314333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 727620735006.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 21101001314333 its reverse (33341310010112), we get a palindrome (54442311324445).

The spelling of 21101001314333 in words is "twenty-one trillion, one hundred one billion, one million, three hundred fourteen thousand, three hundred thirty-three".