2110101113 has 4 divisors (see below), whose sum is σ = 2110193268. Its totient is φ = 2110008960.

The previous prime is 2110101109. The next prime is 2110101131. The reversal of 2110101113 is 3111010112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 973939264 + 1136161849 = 31208^2 + 33707^2 .

It is a cyclic number.

It is not a de Polignac number, because 2110101113 - 2² = 2110101109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2110101094 and 2110101103.

It is not an unprimeable number, because it can be changed into a prime (2110101163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17633 + ... + 67313.

It is an arithmetic number, because the mean of its divisors is an integer number (527548317).

Almost surely, 2^2110101113 is an apocalyptic number.

It is an amenable number.

2110101113 is a deficient number, since it is larger than the sum of its proper divisors (92155).

2110101113 is an equidigital number, since it uses as much as digits as its factorization.

2110101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92154.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 2110101113 is about 45935.8369141131. The cubic root of 2110101113 is about 1282.6290999568.

Adding to 2110101113 its reverse (3111010112), we get a palindrome (5221111225).

The spelling of 2110101113 in words is "two billion, one hundred ten million, one hundred one thousand, one hundred thirteen".