211012233433 has 4 divisors (see below), whose sum is σ = 211205646288. Its totient is φ = 210818820580.

The previous prime is 211012233427. The next prime is 211012233461. The reversal of 211012233433 is 334332210112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211012233433 - 2³⁷ = 73573279961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211012233398 and 211012233407.

It is not an unprimeable number, because it can be changed into a prime (211012233463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96704791 + ... + 96706972.

It is an arithmetic number, because the mean of its divisors is an integer number (52801411572).

Almost surely, 2^211012233433 is an apocalyptic number.

It is an amenable number.

211012233433 is a deficient number, since it is larger than the sum of its proper divisors (193412855).

211012233433 is a wasteful number, since it uses less digits than its factorization.

211012233433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 193412854.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 211012233433 its reverse (334332210112), we get a palindrome (545344443545).

The spelling of 211012233433 in words is "two hundred eleven billion, twelve million, two hundred thirty-three thousand, four hundred thirty-three".