Base | Representation |
---|---|
bin | 101111111110101000100111… |
… | …010110011010111100000111 |
3 | 1000200010120220012112211210220 |
4 | 233332220213112122330013 |
5 | 210124211400240111130 |
6 | 2024441432045515423 |
7 | 62306100032152002 |
oct | 5776504726327407 |
9 | 1020116805484726 |
10 | 211012403441415 |
11 | 6126494872a394 |
12 | 1b7bb74ab72b73 |
13 | 90984cc2c2584 |
14 | 3a170aa5d6539 |
15 | 195ddb460c410 |
hex | bfea2759af07 |
211012403441415 has 16 divisors (see below), whose sum is σ = 337620216235488. Its totient is φ = 112539824925696.
The previous prime is 211012403441353. The next prime is 211012403441429. The reversal of 211012403441415 is 514144304210112.
It is not a de Polignac number, because 211012403441415 - 224 = 211012386664199 is a prime.
It is a super-2 number, since 2×2110124034414152 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7339887 + ... + 21815103.
It is an arithmetic number, because the mean of its divisors is an integer number (21101263514718).
Almost surely, 2211012403441415 is an apocalyptic number.
211012403441415 is a deficient number, since it is larger than the sum of its proper divisors (126607812794073).
211012403441415 is a wasteful number, since it uses less digits than its factorization.
211012403441415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15447058.
The product of its (nonzero) digits is 15360, while the sum is 33.
Adding to 211012403441415 its reverse (514144304210112), we get a palindrome (725156707651527).
The spelling of 211012403441415 in words is "two hundred eleven trillion, twelve billion, four hundred three million, four hundred forty-one thousand, four hundred fifteen".
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