21101332013 has 4 divisors (see below), whose sum is σ = 21103492608. Its totient is φ = 21099171420.

The previous prime is 21101332009. The next prime is 21101332019. The reversal of 21101332013 is 31023310112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21101332013 - 2² = 21101332009 is a prime.

It is a super-3 number, since 3×21101332013³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21101331982 and 21101332000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21101332019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1065581 + ... + 1085202.

It is an arithmetic number, because the mean of its divisors is an integer number (5275873152).

Almost surely, 2^21101332013 is an apocalyptic number.

It is an amenable number.

21101332013 is a deficient number, since it is larger than the sum of its proper divisors (2160595).

21101332013 is an equidigital number, since it uses as much as digits as its factorization.

21101332013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2160594.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 21101332013 its reverse (31023310112), we get a palindrome (52124642125).

The spelling of 21101332013 in words is "twenty-one billion, one hundred one million, three hundred thirty-two thousand, thirteen".