Base | Representation |
---|---|
bin | 111110111000110… |
… | …0001011101100001 |
3 | 12110001120220211022 |
4 | 1331301201131201 |
5 | 13310143242423 |
6 | 545215255225 |
7 | 103201562333 |
oct | 17561413541 |
9 | 5401526738 |
10 | 2110134113 |
11 | 99312aa9a |
12 | 4aa81a515 |
13 | 278228789 |
14 | 160367453 |
15 | c53b9dc8 |
hex | 7dc61761 |
2110134113 has 8 divisors (see below), whose sum is σ = 2144268480. Its totient is φ = 2076077520.
The previous prime is 2110134109. The next prime is 2110134121. The reversal of 2110134113 is 3114310112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2110134113 - 22 = 2110134109 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2110134091 and 2110134100.
It is not an unprimeable number, because it can be changed into a prime (2110134913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36548 + ... + 74538.
It is an arithmetic number, because the mean of its divisors is an integer number (268033560).
Almost surely, 22110134113 is an apocalyptic number.
It is an amenable number.
2110134113 is a deficient number, since it is larger than the sum of its proper divisors (34134367).
2110134113 is an equidigital number, since it uses as much as digits as its factorization.
2110134113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38887.
The product of its (nonzero) digits is 72, while the sum is 17.
The square root of 2110134113 is about 45936.1961093863. The cubic root of 2110134113 is about 1282.6357862935.
Adding to 2110134113 its reverse (3114310112), we get a palindrome (5224444225).
The spelling of 2110134113 in words is "two billion, one hundred ten million, one hundred thirty-four thousand, one hundred thirteen".
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