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21102102433 = 54679385927
BaseRepresentation
bin10011101001110010…
…001000011110100001
32000110122022212120101
4103221302020132201
5321204114234213
613405535142401
71344633624346
oct235162103641
960418285511
1021102102433
118a4964a985
12410b074a01
131cb3b13559
1410428107cd
158378b9bdd
hex4e9c887a1

21102102433 has 4 divisors (see below), whose sum is σ = 21102543040. Its totient is φ = 21101661828.

The previous prime is 21102102421. The next prime is 21102102457. The reversal of 21102102433 is 33420120112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21102102433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21102102433.

It is not an unprimeable number, because it can be changed into a prime (21102102233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138285 + ... + 247642.

It is an arithmetic number, because the mean of its divisors is an integer number (5275635760).

Almost surely, 221102102433 is an apocalyptic number.

It is an amenable number.

21102102433 is a deficient number, since it is larger than the sum of its proper divisors (440607).

21102102433 is an equidigital number, since it uses as much as digits as its factorization.

21102102433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440606.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 21102102433 its reverse (33420120112), we get a palindrome (54522222545).

The spelling of 21102102433 in words is "twenty-one billion, one hundred two million, one hundred two thousand, four hundred thirty-three".

Divisors: 1 54679 385927 21102102433