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211021134000103 = 71713912757459283
BaseRepresentation
bin101111111110110000101111…
…101110110110111111100111
31000200011102102122122011211101
4233332300233232312333213
5210124332240301000403
62024445434244020531
762306526263526610
oct5776605756667747
91020142378564741
10211021134000103
1161268618919349
121b801386991747
139099290cb412b
143a17697d10c07
15195e225d1471d
hexbfec2fbb6fe7

211021134000103 has 16 divisors (see below), whose sum is σ = 257190379165440. Its totient is φ = 169010820567936.

The previous prime is 211021134000101. The next prime is 211021134000109. The reversal of 211021134000103 is 301000431120112.

It is a cyclic number.

It is not a de Polignac number, because 211021134000103 - 21 = 211021134000101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211021134000101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6378713101 + ... + 6378746182.

It is an arithmetic number, because the mean of its divisors is an integer number (16074398697840).

Almost surely, 2211021134000103 is an apocalyptic number.

211021134000103 is a deficient number, since it is larger than the sum of its proper divisors (46169245165337).

211021134000103 is a wasteful number, since it uses less digits than its factorization.

211021134000103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12757459446.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 211021134000103 its reverse (301000431120112), we get a palindrome (512021565120215).

The spelling of 211021134000103 in words is "two hundred eleven trillion, twenty-one billion, one hundred thirty-four million, one hundred three", and thus it is an aban number.

Divisors: 1 7 17 119 139 973 2363 16541 12757459283 89302214981 216876807811 1518137654677 1773286840337 12413007882359 30145876285729 211021134000103