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2110212121999 = 5234034822413
BaseRepresentation
bin11110101101010010011…
…100011010010110001111
321110201211022101202000111
4132231102130122112033
5234033203300400444
64253230145140451
7305313011041012
oct36552234322617
97421738352014
102110212121999
11743a32803333
122a0b8192a727
13123cb89a0c47
14741c5ccd379
1539d58a26234
hex1eb5271a58f

2110212121999 has 4 divisors (see below), whose sum is σ = 2114246944936. Its totient is φ = 2106177299064.

The previous prime is 2110212121951. The next prime is 2110212122041. The reversal of 2110212121999 is 9991212120112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2110212121999 - 217 = 2110211990927 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2110212122999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2017410684 + ... + 2017411729.

It is an arithmetic number, because the mean of its divisors is an integer number (528561736234).

Almost surely, 22110212121999 is an apocalyptic number.

2110212121999 is a deficient number, since it is larger than the sum of its proper divisors (4034822937).

2110212121999 is an equidigital number, since it uses as much as digits as its factorization.

2110212121999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4034822936.

The product of its (nonzero) digits is 11664, while the sum is 40.

The spelling of 2110212121999 in words is "two trillion, one hundred ten billion, two hundred twelve million, one hundred twenty-one thousand, nine hundred ninety-nine".

Divisors: 1 523 4034822413 2110212121999