Base | Representation |
---|---|
bin | 101111111110110000110100… |
… | …011001001011000010100010 |
3 | 1000200011102122002210012110102 |
4 | 233332300310121023002202 |
5 | 210124332420310413442 |
6 | 2024445450120102402 |
7 | 62306531233321121 |
oct | 5776606431130242 |
9 | 1020142562705412 |
10 | 211021212201122 |
11 | 61268658a80994 |
12 | 1b8013a9004a02 |
13 | 90992a426471b |
14 | 3a176a4469ab8 |
15 | 195e22cb10232 |
hex | bfec3464b0a2 |
211021212201122 has 4 divisors (see below), whose sum is σ = 316531818301686. Its totient is φ = 105510606100560.
The previous prime is 211021212201119. The next prime is 211021212201143. The reversal of 211021212201122 is 221102212120112.
211021212201122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 185720503340761 + 25300708860361 = 13627931^2 + 5029981^2 .
It is a junction number, because it is equal to n+sod(n) for n = 211021212201094 and 211021212201103.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52755303050279 + ... + 52755303050282.
Almost surely, 2211021212201122 is an apocalyptic number.
211021212201122 is a deficient number, since it is larger than the sum of its proper divisors (105510606100564).
211021212201122 is a wasteful number, since it uses less digits than its factorization.
211021212201122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105510606100563.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 211021212201122 its reverse (221102212120112), we get a palindrome (432123424321234).
The spelling of 211021212201122 in words is "two hundred eleven trillion, twenty-one billion, two hundred twelve million, two hundred one thousand, one hundred twenty-two".
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