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21102304113434 = 210551152056717
BaseRepresentation
bin1001100110001010000110…
…10101110011001100011010
32202201100201212010100211002
410303011003111303030122
510231220004323112214
6112514133100505002
74305406524262205
oct463050325631432
982640655110732
1021102304113434
1167a6489599605
122449926b4b162
13ba0c2854452b
1452d4dd74493c
15268dbcc6c1de
hex13314357331a

21102304113434 has 4 divisors (see below), whose sum is σ = 31653456170154. Its totient is φ = 10551152056716.

The previous prime is 21102304113433. The next prime is 21102304113437. The reversal of 21102304113434 is 43431140320112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12735441255625 + 8366862857809 = 3568675^2 + 2892553^2 .

It is a junction number, because it is equal to n+sod(n) for n = 21102304113397 and 21102304113406.

It is not an unprimeable number, because it can be changed into a prime (21102304113431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5275576028357 + ... + 5275576028360.

Almost surely, 221102304113434 is an apocalyptic number.

21102304113434 is a deficient number, since it is larger than the sum of its proper divisors (10551152056720).

21102304113434 is a wasteful number, since it uses less digits than its factorization.

21102304113434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10551152056719.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 21102304113434 its reverse (43431140320112), we get a palindrome (64533444433546).

The spelling of 21102304113434 in words is "twenty-one trillion, one hundred two billion, three hundred four million, one hundred thirteen thousand, four hundred thirty-four".

Divisors: 1 2 10551152056717 21102304113434