Base | Representation |
---|---|
bin | 1001100110001010000110… |
… | …10101110011001100011010 |
3 | 2202201100201212010100211002 |
4 | 10303011003111303030122 |
5 | 10231220004323112214 |
6 | 112514133100505002 |
7 | 4305406524262205 |
oct | 463050325631432 |
9 | 82640655110732 |
10 | 21102304113434 |
11 | 67a6489599605 |
12 | 2449926b4b162 |
13 | ba0c2854452b |
14 | 52d4dd74493c |
15 | 268dbcc6c1de |
hex | 13314357331a |
21102304113434 has 4 divisors (see below), whose sum is σ = 31653456170154. Its totient is φ = 10551152056716.
The previous prime is 21102304113433. The next prime is 21102304113437. The reversal of 21102304113434 is 43431140320112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12735441255625 + 8366862857809 = 3568675^2 + 2892553^2 .
It is a junction number, because it is equal to n+sod(n) for n = 21102304113397 and 21102304113406.
It is not an unprimeable number, because it can be changed into a prime (21102304113431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5275576028357 + ... + 5275576028360.
Almost surely, 221102304113434 is an apocalyptic number.
21102304113434 is a deficient number, since it is larger than the sum of its proper divisors (10551152056720).
21102304113434 is a wasteful number, since it uses less digits than its factorization.
21102304113434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10551152056719.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 21102304113434 its reverse (43431140320112), we get a palindrome (64533444433546).
The spelling of 21102304113434 in words is "twenty-one trillion, one hundred two billion, three hundred four million, one hundred thirteen thousand, four hundred thirty-four".
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