Base | Representation |
---|---|
bin | 10011101001110010… |
… | …111011101010110001 |
3 | 2000110122201112012022 |
4 | 103221302323222301 |
5 | 321204142441423 |
6 | 13405543441225 |
7 | 1344635456561 |
oct | 235162735261 |
9 | 60418645168 |
10 | 21102312113 |
11 | 8a49783473 |
12 | 410b156215 |
13 | 1cb3b87b1c |
14 | 1042866da1 |
15 | 83790bdc8 |
hex | 4e9cbbab1 |
21102312113 has 16 divisors (see below), whose sum is σ = 22456967040. Its totient is φ = 19786043904.
The previous prime is 21102312103. The next prime is 21102312139. The reversal of 21102312113 is 31121320112.
It is a cyclic number.
It is not a de Polignac number, because 21102312113 - 24 = 21102312097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21102312091 and 21102312100.
It is not an unprimeable number, because it can be changed into a prime (21102312103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 456995 + ... + 501047.
It is an arithmetic number, because the mean of its divisors is an integer number (1403560440).
Almost surely, 221102312113 is an apocalyptic number.
21102312113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
21102312113 is a deficient number, since it is larger than the sum of its proper divisors (1354654927).
21102312113 is a wasteful number, since it uses less digits than its factorization.
21102312113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44488.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 21102312113 its reverse (31121320112), we get a palindrome (52223632225).
The spelling of 21102312113 in words is "twenty-one billion, one hundred two million, three hundred twelve thousand, one hundred thirteen".
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