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21102312113 = 235935344053
BaseRepresentation
bin10011101001110010…
…111011101010110001
32000110122201112012022
4103221302323222301
5321204142441423
613405543441225
71344635456561
oct235162735261
960418645168
1021102312113
118a49783473
12410b156215
131cb3b87b1c
141042866da1
1583790bdc8
hex4e9cbbab1

21102312113 has 16 divisors (see below), whose sum is σ = 22456967040. Its totient is φ = 19786043904.

The previous prime is 21102312103. The next prime is 21102312139. The reversal of 21102312113 is 31121320112.

It is a cyclic number.

It is not a de Polignac number, because 21102312113 - 24 = 21102312097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21102312091 and 21102312100.

It is not an unprimeable number, because it can be changed into a prime (21102312103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 456995 + ... + 501047.

It is an arithmetic number, because the mean of its divisors is an integer number (1403560440).

Almost surely, 221102312113 is an apocalyptic number.

21102312113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

21102312113 is a deficient number, since it is larger than the sum of its proper divisors (1354654927).

21102312113 is a wasteful number, since it uses less digits than its factorization.

21102312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44488.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 21102312113 its reverse (31121320112), we get a palindrome (52223632225).

The spelling of 21102312113 in words is "twenty-one billion, one hundred two million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 23 59 353 1357 8119 20827 44053 479021 1013219 2599127 15550709 59779921 357666307 917491831 21102312113