Search a number
-
+
21103120131 = 37034373377
BaseRepresentation
bin10011101001110110…
…000000111100000011
32000110201020120120220
4103221312000330003
5321204344321011
613410013034123
71344645363402
oct235166007403
960421216526
1021103120131
118a4a185555
12410b485943
131cb40ab842
1410429d7639
15837a1b506
hex4e9d80f03

21103120131 has 4 divisors (see below), whose sum is σ = 28137493512. Its totient is φ = 14068746752.

The previous prime is 21103120099. The next prime is 21103120133. The reversal of 21103120131 is 13102130112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21103120131 - 25 = 21103120099 is a prime.

It is a super-2 number, since 2×211031201312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21103120131.

It is not an unprimeable number, because it can be changed into a prime (21103120133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3517186686 + ... + 3517186691.

It is an arithmetic number, because the mean of its divisors is an integer number (7034373378).

Almost surely, 221103120131 is an apocalyptic number.

21103120131 is a deficient number, since it is larger than the sum of its proper divisors (7034373381).

21103120131 is an equidigital number, since it uses as much as digits as its factorization.

21103120131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7034373380.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 21103120131 its reverse (13102130112), we get a palindrome (34205250243).

The spelling of 21103120131 in words is "twenty-one billion, one hundred three million, one hundred twenty thousand, one hundred thirty-one".

Divisors: 1 3 7034373377 21103120131