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211103130023 = 1661912702517
BaseRepresentation
bin1100010010011010111…
…0100010000110100111
3202011220010210010112022
43010212232202012213
511424314400130043
6240551320413355
721152221666322
oct3044656420647
9664803703468
10211103130023
118158a239115
1234ab601725b
1316ba3714bb6
14a3089597b9
1557580d5868
hex3126ba21a7

211103130023 has 4 divisors (see below), whose sum is σ = 211115849160. Its totient is φ = 211090410888.

The previous prime is 211103130013. The next prime is 211103130041. The reversal of 211103130023 is 320031301112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211103130023 - 26 = 211103129959 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211103129983 and 211103130010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211103130013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6334640 + ... + 6367877.

It is an arithmetic number, because the mean of its divisors is an integer number (52778962290).

Almost surely, 2211103130023 is an apocalyptic number.

211103130023 is a deficient number, since it is larger than the sum of its proper divisors (12719137).

211103130023 is a wasteful number, since it uses less digits than its factorization.

211103130023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12719136.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 211103130023 its reverse (320031301112), we get a palindrome (531134431135).

The spelling of 211103130023 in words is "two hundred eleven billion, one hundred three million, one hundred thirty thousand, twenty-three".

Divisors: 1 16619 12702517 211103130023