211111100113 has 4 divisors (see below), whose sum is σ = 211114944820. Its totient is φ = 211107255408.

The previous prime is 211111100107. The next prime is 211111100141. The reversal of 211111100113 is 311001111112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 147892546624 + 63218553489 = 384568^2 + 251433^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211111100113 is a prime.

It is a super-3 number, since 3×211111100113³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211111100093 and 211111100102.

It is not an unprimeable number, because it can be changed into a prime (211111100183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838778 + ... + 1950211.

It is an arithmetic number, because the mean of its divisors is an integer number (52778736205).

Almost surely, 2^211111100113 is an apocalyptic number.

It is an amenable number.

211111100113 is a deficient number, since it is larger than the sum of its proper divisors (3844707).

211111100113 is an equidigital number, since it uses as much as digits as its factorization.

211111100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3844706.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 211111100113 its reverse (311001111112), we get a palindrome (522112211225).

It can be divided in two parts, 2111 and 11100113, that added together give a square (11102224 = 3332²).

The spelling of 211111100113 in words is "two hundred eleven billion, one hundred eleven million, one hundred thousand, one hundred thirteen".