Base | Representation |
---|---|
bin | 110000000000000100101110… |
… | …000011100111101010001111 |
3 | 1000200111001011111020202212022 |
4 | 300000010232003213222033 |
5 | 210132321420322413403 |
6 | 2024555105322400355 |
7 | 62316200551560311 |
oct | 6000045603475217 |
9 | 1020431144222768 |
10 | 211111300201103 |
11 | 612a2888337735 |
12 | 1b81694b3600bb |
13 | 90a49303884a3 |
14 | 3a1bbacd137b1 |
15 | 1961751a70d38 |
hex | c0012e0e7a8f |
211111300201103 has 4 divisors (see below), whose sum is σ = 211139422134840. Its totient is φ = 211083178267368.
The previous prime is 211111300201097. The next prime is 211111300201133. The reversal of 211111300201103 is 301102003111112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211111300201103 - 238 = 210836422294159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211111300201133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14060955608 + ... + 14060970621.
It is an arithmetic number, because the mean of its divisors is an integer number (52784855533710).
Almost surely, 2211111300201103 is an apocalyptic number.
211111300201103 is a deficient number, since it is larger than the sum of its proper divisors (28121933737).
211111300201103 is an equidigital number, since it uses as much as digits as its factorization.
211111300201103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28121933736.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 211111300201103 its reverse (301102003111112), we get a palindrome (512213303312215).
The spelling of 211111300201103 in words is "two hundred eleven trillion, one hundred eleven billion, three hundred million, two hundred one thousand, one hundred three".
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