211121020120121 has 4 divisors (see below), whose sum is σ = 211153746993744. Its totient is φ = 211088293246500.

The previous prime is 211121020120117. The next prime is 211121020120133. The reversal of 211121020120121 is 121021020121112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211121020120121 - 2² = 211121020120117 is a prime.

It is a super-2 number, since 2×211121020120121² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 211121020120121.

It is not an unprimeable number, because it can be changed into a prime (211121020120321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16363427135 + ... + 16363440036.

It is an arithmetic number, because the mean of its divisors is an integer number (52788436748436).

Almost surely, 2^{211121020120121} is an apocalyptic number.

It is an amenable number.

211121020120121 is a deficient number, since it is larger than the sum of its proper divisors (32726873623).

211121020120121 is an equidigital number, since it uses as much as digits as its factorization.

211121020120121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32726873622.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 211121020120121 its reverse (121021020121112), we get a palindrome (332142040241233).

Subtracting from 211121020120121 its reverse (121021020121112), we obtain a palindrome (90099999999009).

The spelling of 211121020120121 in words is "two hundred eleven trillion, one hundred twenty-one billion, twenty million, one hundred twenty thousand, one hundred twenty-one".