Base | Representation |
---|---|
bin | 11110101110001110101… |
… | …001010010010101101111 |
3 | 21110211102200220110120101 |
4 | 132232032221102111233 |
5 | 234042240331130111 |
6 | 4253514305131531 |
7 | 305350024003600 |
oct | 36561651222557 |
9 | 7424380813511 |
10 | 2111222130031 |
11 | 744400942313 |
12 | 2a1204029ba7 |
13 | 12411a003531 |
14 | 742800c3da7 |
15 | 39db7532bc1 |
hex | 1eb8ea5256f |
2111222130031 has 12 divisors (see below), whose sum is σ = 2468636398272. Its totient is φ = 1800242696448.
The previous prime is 2111222130023. The next prime is 2111222130091. The reversal of 2111222130031 is 1300312221112.
It is not a de Polignac number, because 2111222130031 - 23 = 2111222130023 is a prime.
It is a super-2 number, since 2×21112221300312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2111222129990 and 2111222130008.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2111222130001) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 111612735 + ... + 111631648.
It is an arithmetic number, because the mean of its divisors is an integer number (205719699856).
Almost surely, 22111222130031 is an apocalyptic number.
2111222130031 is a deficient number, since it is larger than the sum of its proper divisors (357414268241).
2111222130031 is a wasteful number, since it uses less digits than its factorization.
2111222130031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223244590 (or 223244583 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2111222130031 its reverse (1300312221112), we get a palindrome (3411534351143).
The spelling of 2111222130031 in words is "two trillion, one hundred eleven billion, two hundred twenty-two million, one hundred thirty thousand, thirty-one".
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