2111224114031 has 4 divisors (see below), whose sum is σ = 2114921529864. Its totient is φ = 2107526698200.

The previous prime is 2111224113991. The next prime is 2111224114033. The reversal of 2111224114031 is 1304114221112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111224114031 - 2¹⁸ = 2111223851887 is a prime.

It is a super-2 number, since 2×2111224114031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2111224113988 and 2111224114006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111224114033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1848707060 + ... + 1848708201.

It is an arithmetic number, because the mean of its divisors is an integer number (528730382466).

Almost surely, 2^{2111224114031} is an apocalyptic number.

2111224114031 is a deficient number, since it is larger than the sum of its proper divisors (3697415833).

2111224114031 is an equidigital number, since it uses as much as digits as its factorization.

2111224114031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3697415832.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 2111224114031 its reverse (1304114221112), we get a palindrome (3415338335143).

The spelling of 2111224114031 in words is "two trillion, one hundred eleven billion, two hundred twenty-four million, one hundred fourteen thousand, thirty-one".