Base | Representation |
---|---|
bin | 1001100110011110000001… |
… | …10111111101010001100111 |
3 | 2202202101100021121112101122 |
4 | 10303033000313331101213 |
5 | 10231403411014413330 |
6 | 112523102310044155 |
7 | 4306235553155444 |
oct | 463170067752147 |
9 | 82671307545348 |
10 | 21113000154215 |
11 | 67aaa78199332 |
12 | 244ba1104965b |
13 | ba1c414b5c48 |
14 | 52dc360d09cb |
15 | 2692e6cb95e5 |
hex | 1333c0dfd467 |
21113000154215 has 4 divisors (see below), whose sum is σ = 25335600185064. Its totient is φ = 16890400123368.
The previous prime is 21113000154209. The next prime is 21113000154223. The reversal of 21113000154215 is 51245100031112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21113000154215 - 24 = 21113000154199 is a prime.
It is a super-2 number, since 2×211130001542152 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2111300015417 + ... + 2111300015426.
It is an arithmetic number, because the mean of its divisors is an integer number (6333900046266).
Almost surely, 221113000154215 is an apocalyptic number.
21113000154215 is a deficient number, since it is larger than the sum of its proper divisors (4222600030849).
21113000154215 is an equidigital number, since it uses as much as digits as its factorization.
21113000154215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4222600030848.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 21113000154215 its reverse (51245100031112), we get a palindrome (72358100185327).
The spelling of 21113000154215 in words is "twenty-one trillion, one hundred thirteen billion, one hundred fifty-four thousand, two hundred fifteen".
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