Base | Representation |
---|---|
bin | 110000000000010110001001… |
… | …011001001001110110010011 |
3 | 1000200112211110120122002201120 |
4 | 300000112021121021312103 |
5 | 210133123231141121003 |
6 | 2025011442210533323 |
7 | 62320432346155434 |
oct | 6000261131116623 |
9 | 1020484416562646 |
10 | 211130012442003 |
11 | 612aa80a96a236 |
12 | 1b81a4b1b97243 |
13 | 90a6623022995 |
14 | 3a1ca6618348b |
15 | 1961e99718853 |
hex | c00589649d93 |
211130012442003 has 16 divisors (see below), whose sum is σ = 283193262326016. Its totient is φ = 139910057512160.
The previous prime is 211130012441923. The next prime is 211130012442071. The reversal of 211130012442003 is 300244210031112.
It is a cyclic number.
It is not a de Polignac number, because 211130012442003 - 225 = 211129978887571 is a prime.
It is not an unprimeable number, because it can be changed into a prime (211130012442103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 242094325 + ... + 242964857.
It is an arithmetic number, because the mean of its divisors is an integer number (17699578895376).
Almost surely, 2211130012442003 is an apocalyptic number.
211130012442003 is a deficient number, since it is larger than the sum of its proper divisors (72063249884013).
211130012442003 is a wasteful number, since it uses less digits than its factorization.
211130012442003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1354794.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 211130012442003 its reverse (300244210031112), we get a palindrome (511374222473115).
The spelling of 211130012442003 in words is "two hundred eleven trillion, one hundred thirty billion, twelve million, four hundred forty-two thousand, three".
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