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21113014113 = 322345890457
BaseRepresentation
bin10011101010011011…
…110000011101100001
32000111101212020120200
4103222123300131201
5321214412422423
613411005055413
71345125442002
oct235233603541
960441766520
1021113014113
118a54822aa4
124112857569
131cb6164079
1410440511a9
15838822d43
hex4ea6f0761

21113014113 has 6 divisors (see below), whose sum is σ = 30496575954. Its totient is φ = 14075342736.

The previous prime is 21113014103. The next prime is 21113014127. The reversal of 21113014113 is 31141031112.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 19001795409 + 2111218704 = 137847^2 + 45948^2 .

It is not a de Polignac number, because 21113014113 - 25 = 21113014081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (21113014103) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1172945220 + ... + 1172945237.

It is an arithmetic number, because the mean of its divisors is an integer number (5082762659).

Almost surely, 221113014113 is an apocalyptic number.

It is an amenable number.

21113014113 is a deficient number, since it is larger than the sum of its proper divisors (9383561841).

21113014113 is a wasteful number, since it uses less digits than its factorization.

21113014113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2345890463 (or 2345890460 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 21113014113 its reverse (31141031112), we get a palindrome (52254045225).

The spelling of 21113014113 in words is "twenty-one billion, one hundred thirteen million, fourteen thousand, one hundred thirteen".

Divisors: 1 3 9 2345890457 7037671371 21113014113