Base | Representation |
---|---|
bin | 1100010010100001011… |
… | …0001101111100010101 |
3 | 202011222000221001000201 |
4 | 3010220112031330111 |
5 | 11424343324413141 |
6 | 240554131140501 |
7 | 21153002012422 |
oct | 3045026157425 |
9 | 664860831021 |
10 | 211130310421 |
11 | 815a3613158 |
12 | 34b03144731 |
13 | 16ba9240684 |
14 | a30c3d2d49 |
15 | 575a6a4031 |
hex | 312858df15 |
211130310421 has 4 divisors (see below), whose sum is σ = 214281509152. Its totient is φ = 207979111692.
The previous prime is 211130310389. The next prime is 211130310427. The reversal of 211130310421 is 124013031112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211130310421 - 25 = 211130310389 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211130310427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1575599265 + ... + 1575599398.
It is an arithmetic number, because the mean of its divisors is an integer number (53570377288).
Almost surely, 2211130310421 is an apocalyptic number.
It is an amenable number.
211130310421 is a deficient number, since it is larger than the sum of its proper divisors (3151198731).
211130310421 is an equidigital number, since it uses as much as digits as its factorization.
211130310421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3151198730.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 211130310421 its reverse (124013031112), we get a palindrome (335143341533).
The spelling of 211130310421 in words is "two hundred eleven billion, one hundred thirty million, three hundred ten thousand, four hundred twenty-one".
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