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21113100033000 = 2335323319870547
BaseRepresentation
bin1001100110011110001101…
…10100111101101111101000
32202202101121020112220022220
410303033012310331233220
510231404112102024000
6112523120234514040
74306241205134313
oct463170664755750
982671536486286
1021113100033000
116800019607788
12244ba3a595920
13ba1c590b6511
1452dc4548d97a
152693009481a0
hex1333c6d3dbe8

21113100033000 has 256 divisors, whose sum is σ = 70954236887040. Its totient is φ = 5211648288000.

The previous prime is 21113100032989. The next prime is 21113100033041. The reversal of 21113100033000 is 33000131112.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2796274 + ... + 7074273.

It is an arithmetic number, because the mean of its divisors is an integer number (277164987840).

Almost surely, 221113100033000 is an apocalyptic number.

21113100033000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

21113100033000 is an abundant number, since it is smaller than the sum of its proper divisors (49841136854040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21113100033000 is a wasteful number, since it uses less digits than its factorization.

21113100033000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9870625 (or 9870611 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 21113100033000 its reverse (33000131112), we get a palindrome (21146100164112).

The spelling of 21113100033000 in words is "twenty-one trillion, one hundred thirteen billion, one hundred million, thirty-three thousand".