Base | Representation |
---|---|
bin | 1100010010100001100… |
… | …0110110110010010001 |
3 | 202011222002020011200210 |
4 | 3010220120312302101 |
5 | 11424344014031001 |
6 | 240554154034333 |
7 | 21153010622613 |
oct | 3045030666221 |
9 | 664862204623 |
10 | 211131002001 |
11 | 815a3a45807 |
12 | 34b034189a9 |
13 | 16ba94233aa |
14 | a30c532db3 |
15 | 575a78ddd6 |
hex | 3128636c91 |
211131002001 has 4 divisors (see below), whose sum is σ = 281508002672. Its totient is φ = 140754001332.
The previous prime is 211131001997. The next prime is 211131002003. The reversal of 211131002001 is 100200131112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 211131002001 - 22 = 211131001997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211131002003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35188500331 + ... + 35188500336.
It is an arithmetic number, because the mean of its divisors is an integer number (70377000668).
Almost surely, 2211131002001 is an apocalyptic number.
It is an amenable number.
211131002001 is a deficient number, since it is larger than the sum of its proper divisors (70377000671).
211131002001 is an equidigital number, since it uses as much as digits as its factorization.
211131002001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70377000670.
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 211131002001 its reverse (100200131112), we get a palindrome (311331133113).
The spelling of 211131002001 in words is "two hundred eleven billion, one hundred thirty-one million, two thousand, one".
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