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211131002003 is a prime number
BaseRepresentation
bin1100010010100001100…
…0110110110010010011
3202011222002020011200212
43010220120312302103
511424344014031003
6240554154034335
721153010622615
oct3045030666223
9664862204625
10211131002003
11815a3a45809
1234b034189ab
1316ba94233ac
14a30c532db5
15575a78ddd8
hex3128636c93

211131002003 has 2 divisors, whose sum is σ = 211131002004. Its totient is φ = 211131002002.

The previous prime is 211131001997. The next prime is 211131002021. The reversal of 211131002003 is 300200131112.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211131002003 is a prime.

It is not a weakly prime, because it can be changed into another prime (211131052003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565501001 + 105565501002.

It is an arithmetic number, because the mean of its divisors is an integer number (105565501002).

Almost surely, 2211131002003 is an apocalyptic number.

211131002003 is a deficient number, since it is larger than the sum of its proper divisors (1).

211131002003 is an equidigital number, since it uses as much as digits as its factorization.

211131002003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 211131002003 its reverse (300200131112), we get a palindrome (511331133115).

The spelling of 211131002003 in words is "two hundred eleven billion, one hundred thirty-one million, two thousand, three".