21113100414313 has 4 divisors (see below), whose sum is σ = 21113374605568. Its totient is φ = 21112826223060.

The previous prime is 21113100414311. The next prime is 21113100414323. The reversal of 21113100414313 is 31341400131112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21113100414313 - 2¹ = 21113100414311 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21113100414311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136980093 + ... + 137134138.

It is an arithmetic number, because the mean of its divisors is an integer number (5278343651392).

Almost surely, 2^{21113100414313} is an apocalyptic number.

It is an amenable number.

21113100414313 is a deficient number, since it is larger than the sum of its proper divisors (274191255).

21113100414313 is an equidigital number, since it uses as much as digits as its factorization.

21113100414313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 274191254.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 21113100414313 its reverse (31341400131112), we get a palindrome (52454500545425).

The spelling of 21113100414313 in words is "twenty-one trillion, one hundred thirteen billion, one hundred million, four hundred fourteen thousand, three hundred thirteen".