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2111312143 = 29286125447
BaseRepresentation
bin111110111011000…
…0001000100001111
312110010210202210001
41331312001010033
513310443442033
6545300425131
7103214566663
oct17566010417
95403722701
102111312143
11993865076
124ab0a81a7
1327854ba35
141605928a3
15c554de7d
hex7dd8110f

2111312143 has 8 divisors (see below), whose sum is σ = 2184965280. Its totient is φ = 2037715680.

The previous prime is 2111312087. The next prime is 2111312153. The reversal of 2111312143 is 3412131112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111312143 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2111312143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111312153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70246 + ... + 95692.

It is an arithmetic number, because the mean of its divisors is an integer number (273120660).

Almost surely, 22111312143 is an apocalyptic number.

2111312143 is a deficient number, since it is larger than the sum of its proper divisors (73653137).

2111312143 is a wasteful number, since it uses less digits than its factorization.

2111312143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28337.

The product of its digits is 144, while the sum is 19.

The square root of 2111312143 is about 45949.0167794698. The cubic root of 2111312143 is about 1282.8744286833.

Adding to 2111312143 its reverse (3412131112), we get a palindrome (5523443255).

The spelling of 2111312143 in words is "two billion, one hundred eleven million, three hundred twelve thousand, one hundred forty-three".

Divisors: 1 29 2861 25447 82969 737963 72803867 2111312143