Base | Representation |
---|---|
bin | 1100010010100001100… |
… | …1111111100101101001 |
3 | 202011222002210022202020 |
4 | 3010220121333211221 |
5 | 11424344103101301 |
6 | 240554204255053 |
7 | 21153013304163 |
oct | 3045031774551 |
9 | 664862708666 |
10 | 211131300201 |
11 | 815a4129858 |
12 | 34b03541489 |
13 | 16ba94c9043 |
14 | a30c5ad933 |
15 | 575a7ec436 |
hex | 312867f969 |
211131300201 has 4 divisors (see below), whose sum is σ = 281508400272. Its totient is φ = 140754200132.
The previous prime is 211131300179. The next prime is 211131300223. The reversal of 211131300201 is 102003131112.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (211131300179) and next prime (211131300223).
It is a cyclic number.
It is not a de Polignac number, because 211131300201 - 227 = 210997082473 is a prime.
It is not an unprimeable number, because it can be changed into a prime (211131300251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35188550031 + ... + 35188550036.
It is an arithmetic number, because the mean of its divisors is an integer number (70377100068).
Almost surely, 2211131300201 is an apocalyptic number.
It is an amenable number.
211131300201 is a deficient number, since it is larger than the sum of its proper divisors (70377100071).
211131300201 is an equidigital number, since it uses as much as digits as its factorization.
211131300201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70377100070.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 211131300201 its reverse (102003131112), we get a palindrome (313134431313).
The spelling of 211131300201 in words is "two hundred eleven billion, one hundred thirty-one million, three hundred thousand, two hundred one".
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