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2111313103 = 8632446481
BaseRepresentation
bin111110111011000…
…0001010011001111
312110010210211002121
41331312001103033
513310444004403
6545300433411
7103214602534
oct17566012317
95403724077
102111313103
11993865869
124ab0a8867
1327854c2c3
14160592d8b
15c554e3bd
hex7dd814cf

2111313103 has 4 divisors (see below), whose sum is σ = 2113760448. Its totient is φ = 2108865760.

The previous prime is 2111313101. The next prime is 2111313109. The reversal of 2111313103 is 3013131112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111313103 - 21 = 2111313101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111313101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1222378 + ... + 1224103.

It is an arithmetic number, because the mean of its divisors is an integer number (528440112).

Almost surely, 22111313103 is an apocalyptic number.

2111313103 is a deficient number, since it is larger than the sum of its proper divisors (2447345).

2111313103 is an equidigital number, since it uses as much as digits as its factorization.

2111313103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2447344.

The product of its (nonzero) digits is 54, while the sum is 16.

The square root of 2111313103 is about 45949.0272258293. The cubic root of 2111313103 is about 1282.8746231215.

Adding to 2111313103 its reverse (3013131112), we get a palindrome (5124444215).

The spelling of 2111313103 in words is "two billion, one hundred eleven million, three hundred thirteen thousand, one hundred three".

Divisors: 1 863 2446481 2111313103