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211131311213 = 263802780651
BaseRepresentation
bin1100010010100001101…
…0000010010001101101
3202011222002210212212002
43010220122002101231
511424344103424323
6240554204422045
721153013351244
oct3045032022155
9664862725762
10211131311213
11815a4137059
1234b03547925
1316ba9501064
14a30c5b395b
15575a800828
hex312868246d

211131311213 has 4 divisors (see below), whose sum is σ = 211934092128. Its totient is φ = 210328530300.

The previous prime is 211131311201. The next prime is 211131311227. The reversal of 211131311213 is 312113131112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211131311213 - 218 = 211131049069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211131311233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401390063 + ... + 401390588.

It is an arithmetic number, because the mean of its divisors is an integer number (52983523032).

Almost surely, 2211131311213 is an apocalyptic number.

It is an amenable number.

211131311213 is a deficient number, since it is larger than the sum of its proper divisors (802780915).

211131311213 is an equidigital number, since it uses as much as digits as its factorization.

211131311213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 802780914.

The product of its digits is 108, while the sum is 20.

Adding to 211131311213 its reverse (312113131112), we get a palindrome (523244442325).

The spelling of 211131311213 in words is "two hundred eleven billion, one hundred thirty-one million, three hundred eleven thousand, two hundred thirteen".

Divisors: 1 263 802780651 211131311213